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TCS Xplore 2023 Ion Proctored Exam ( IPA) 6 - JAVA coding solution ( 15 marks )

 Problem Statement : 



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Write a program to take a integer  number and check whether this number is perfect number or not .

if number is perfect then print "Given number is Perfect number" else print  "Given number is not Perfect number".

A number whose sum of factors (excluding the number itself) is equal to the number is called a perfect number. In other words, if the sum of positive divisors (excluding the number itself) of a number equals the number itself is called a perfect number .

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Example : 

First, we find the factors of 496 i.e. 1, 2, 4, 8, 16, 31, 62, 124, and 248. Let's find the sum of factors (1 + 2 + 4 + 8 + 16 + 31 + 62 + 124 +248 = 496). We observe that the sum of factors is equal to the number itself. Hence, the number 496 is a perfect number.


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If number is 6 then factors of 6 is 1,2,3 and sum of factor is 1+2+3 is also 6 . So 6 is a perfect number .

Approach : 

  1. Read or initialize a number (n).
  2. Declare a variable (s) for storing sum.
  3. Find the factors of the given number (n) by using a loop (for/ while).
  4. Calculate the sum of factors and store it in a variable s.
  5. Compare the sum (s) with the number (n):
    • If both (s and n) are equal, then the given number is a perfect number.
    • Else, the number is not a perfect number.

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Code :


import java.util.*;
public class Perfect {
    public static void main(String[] args) {
        Scanner sc=new Scanner(System.in);
        int n=sc.nextInt();

        int sum=0;
        for(int i=1;i<n;i++){
            if(n%i==0){
                sum+=i;
            }
        }
        if(sum==n){
            System.out.println("Given number is perfect number ");
        }
        else{
            System.out.println("Given number is not a perfect number ");
        }
    }
   
}

Thank You !

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