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TCS IPA previous year problem 10 , solved [input + output ] in JAVA - (35 marks )

 Problem Statement : 



Video Link : 


 Create a class Phone with below attributes: phoneId - int os - String brand - String price - int

Write getters, setters and parameterized constructor in the above mentioned attribute sequence as required.

Create class Solution with main method.

Implement two static methods - findPriceForGivenBrand and getPhoneIdBasedOnOs in Solution class.

findPriceForGivenBrand method: This method will take two input parameters - array of Phone objects and string parameter brand. The method will return the sum of the price attribute from phone objects for the brand passed as parameter. If no phones with the given brand is present in the array of phone objects, then the method should return 0.

getPhoneIdBasedOnOs method: This method will take a String parameter os, along with the array of Phone objects. The method will return the phone object, if the input String parameter matches with the os attribute of the phone object and its price attribute is greater than or equal to 50000. If any of the conditions are not met, then the method should return null.

Note : No phone object would have the same value for os attribute. All phone object would have the price greater than 0. All the searches should be case insensitive.

These above mentioned static methods should be called from the main method.

For findPriceForGivenBrand method - The main method should print the price as it is if the returned price is greater than 0, or it should print "The given Brand is not available".

For getPhoneIdBasedOnOs method - The main method should print the phoneId of the returned phone object. If the returned value is null then it should print "No phones are available with specified os and price range".

Before calling these static methods in main, use Scanner object to read the values of four Phone objects referring attributes in the above mentioned attribute sequence. Next, read the value for brand and os.


Input : 

111

iOS

Apple

30000

222

android

Samsung

50000

333

Symbian

HTC

12000

444

Paranoid

HTC

89000

Blackberry

aNdRoid

[ Note : Please when you type input , if you copy this input ... all spaces are also be copied so write input by your own or you can copy from my github link given below . ]

gitHub Link :

Output : 

This brand  is not available 

222

Code : 

import java.util.Scanner;

class Phone {
    int phoneId;
    String os;
    String brand;
    int price;

    public Phone(int phoneId, String os, String brand, int price) {
        this.phoneId = phoneId;
        this.os = os;
        this.brand = brand;
        this.price = price;

    }
}

public class Solution2 {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);

        Phone arr[] = new Phone[4];

        for (int i = 0; i < arr.length; i++) {
            int a = sc.nextInt();
            sc.nextLine();
            String b = sc.nextLine();
            String c = sc.nextLine();
            int d = sc.nextInt();
            sc.nextLine();

            arr[i] = new Phone(a, b, c, d);
        }
        String inputBrand = sc.nextLine();
        String inputos = sc.nextLine();
        int sum = findPriceForGivenBrand(arr, inputBrand);
        Phone obj = getPhoneIdBasedOnOs(arr, inputos);

        if (sum == 0) {
            System.out.println("The given Brand is not available");
        } else {
            System.out.println(sum);
        }

        if (obj == null) {
            System.out.println("No phones are available with specified os and
price range");
        } else {
            System.out.println(obj.phoneId);
        }

    }

    public static int findPriceForGivenBrand(Phone arr[], String inputBrand) {
        int sum = 0;
        for (int i = 0; i < arr.length; i++) {
            if (arr[i].brand.equalsIgnoreCase(inputBrand)) {
                sum += arr[i].price;
            }
        }
        return sum;
    }

    public static Phone getPhoneIdBasedOnOs(Phone arr[], String inputos) {

        for (int i = 0; i < arr.length; i++) {
            if (arr[i].os.equalsIgnoreCase(inputos)) {
                if (arr[i].price >= 50000) {
                    return arr[i];
                }
            }
        }

        return null;

    }

}



Thank You !

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